Base | Representation |
---|---|
bin | 11000110001011111… |
… | …00011010000001001 |
3 | 1021022220100000211222 |
4 | 30120233203100021 |
5 | 204214301121413 |
6 | 10035425331425 |
7 | 650405210123 |
oct | 143057432011 |
9 | 37286300758 |
10 | 13300020233 |
11 | 5705573065 |
12 | 26b2196b75 |
13 | 133c5a8a76 |
14 | 902546213 |
15 | 52c966b08 |
hex | 318be3409 |
13300020233 has 4 divisors (see below), whose sum is σ = 13317921408. Its totient is φ = 13282119060.
The previous prime is 13300020203. The next prime is 13300020247. The reversal of 13300020233 is 33202000331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13300020233 - 26 = 13300020169 is a prime.
It is a super-4 number, since 4×133000202334 (a number of 42 digits) contains 4444 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13300020203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8949473 + ... + 8950958.
It is an arithmetic number, because the mean of its divisors is an integer number (3329480352).
Almost surely, 213300020233 is an apocalyptic number.
It is an amenable number.
13300020233 is a deficient number, since it is larger than the sum of its proper divisors (17901175).
13300020233 is an equidigital number, since it uses as much as digits as its factorization.
13300020233 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17901174.
The product of its (nonzero) digits is 324, while the sum is 17.
Adding to 13300020233 its reverse (33202000331), we get a palindrome (46502020564).
The spelling of 13300020233 in words is "thirteen billion, three hundred million, twenty thousand, two hundred thirty-three".
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