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133000514555203 = 1063125118075781
BaseRepresentation
bin11110001111011010011000…
…011011001100110101000011
3122102220201120112111200021001
4132033122120123030311003
5114413040023211231303
61150511332022112431
740004653510463521
oct3617323033146503
9572821515450231
10133000514555203
1139418224171939
1212b0048327b717
135929b82895209
1424bb38b559311
1510599ae07d31d
hex78f6986ccd43

133000514555203 has 4 divisors (see below), whose sum is σ = 133125632632048. Its totient is φ = 132875396478360.

The previous prime is 133000514555179. The next prime is 133000514555213. The reversal of 133000514555203 is 302555415000331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133000514555203 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133000514555213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 62559036828 + ... + 62559038953.

It is an arithmetic number, because the mean of its divisors is an integer number (33281408158012).

Almost surely, 2133000514555203 is an apocalyptic number.

133000514555203 is a deficient number, since it is larger than the sum of its proper divisors (125118076845).

133000514555203 is a wasteful number, since it uses less digits than its factorization.

133000514555203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 125118076844.

The product of its (nonzero) digits is 135000, while the sum is 37.

Adding to 133000514555203 its reverse (302555415000331), we get a palindrome (435555929555534).

The spelling of 133000514555203 in words is "one hundred thirty-three trillion, five hundred fourteen million, five hundred fifty-five thousand, two hundred three".

Divisors: 1 1063 125118075781 133000514555203