13300122444041 has 4 divisors (see below), whose sum is σ = 13333289832084. Its totient is φ = 13266955056000.

The previous prime is 13300122444029. The next prime is 13300122444097. The reversal of 13300122444041 is 14044422100331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 13051890307600 + 248232136441 = 3612740^2 + 498229^2 .

It is a cyclic number.

It is not a de Polignac number, because 13300122444041 - 2³⁰ = 13299048702217 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13300122443995 and 13300122444013.

It is not an unprimeable number, because it can be changed into a prime (13300122444541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16583693420 + ... + 16583694221.

It is an arithmetic number, because the mean of its divisors is an integer number (3333322458021).

Almost surely, 2^{13300122444041} is an apocalyptic number.

It is an amenable number.

13300122444041 is a deficient number, since it is larger than the sum of its proper divisors (33167388043).

13300122444041 is an equidigital number, since it uses as much as digits as its factorization.

13300122444041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33167388042.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 13300122444041 its reverse (14044422100331), we get a palindrome (27344544544372).

The spelling of 13300122444041 in words is "thirteen trillion, three hundred billion, one hundred twenty-two million, four hundred forty-four thousand, forty-one".