Base | Representation |
---|---|
bin | 11110001111011011000011… |
… | …110111101000110001111001 |
3 | 122102220210110100000100112020 |
4 | 132033123003313220301321 |
5 | 114413043021304230014 |
6 | 1150511532220305053 |
7 | 40005010541016123 |
oct | 3617330367506171 |
9 | 572823410010466 |
10 | 133001243430009 |
11 | 39418568643309 |
12 | 12b006473a2189 |
13 | 5929c6a8a4396 |
14 | 24bb41a28c213 |
15 | 1059a030561a9 |
hex | 78f6c3de8c79 |
133001243430009 has 4 divisors (see below), whose sum is σ = 177334991240016. Its totient is φ = 88667495620004.
The previous prime is 133001243429981. The next prime is 133001243430017. The reversal of 133001243430009 is 900034342100331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 133001243430009 - 27 = 133001243429881 is a prime.
It is not an unprimeable number, because it can be changed into a prime (133001243430109) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22166873904999 + ... + 22166873905004.
It is an arithmetic number, because the mean of its divisors is an integer number (44333747810004).
Almost surely, 2133001243430009 is an apocalyptic number.
It is an amenable number.
133001243430009 is a deficient number, since it is larger than the sum of its proper divisors (44333747810007).
133001243430009 is an equidigital number, since it uses as much as digits as its factorization.
133001243430009 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44333747810006.
The product of its (nonzero) digits is 23328, while the sum is 33.
The spelling of 133001243430009 in words is "one hundred thirty-three trillion, one billion, two hundred forty-three million, four hundred thirty thousand, nine".
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