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1330013121011 = 2295807917559
BaseRepresentation
bin10011010110101010111…
…101011010100111110011
311201010222220022222020122
4103112222331122213303
5133242331324333021
62454555525000455
7165042651666041
oct23265275324763
94633886288218
101330013121011
11473067808233
1219592285312b
139855c104843
144853164b391
15248e3c91bab
hex135aaf5a9f3

1330013121011 has 4 divisors (see below), whose sum is σ = 1335821038800. Its totient is φ = 1324205203224.

The previous prime is 1330013120903. The next prime is 1330013121013. The reversal of 1330013121011 is 1101213100331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1330013121011 - 210 = 1330013119987 is a prime.

It is a super-2 number, since 2×13300131210112 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1330013121013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2903958551 + ... + 2903959008.

It is an arithmetic number, because the mean of its divisors is an integer number (333955259700).

Almost surely, 21330013121011 is an apocalyptic number.

1330013121011 is a deficient number, since it is larger than the sum of its proper divisors (5807917789).

1330013121011 is an equidigital number, since it uses as much as digits as its factorization.

1330013121011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5807917788.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1330013121011 its reverse (1101213100331), we get a palindrome (2431226221342).

The spelling of 1330013121011 in words is "one trillion, three hundred thirty billion, thirteen million, one hundred twenty-one thousand, eleven".

Divisors: 1 229 5807917559 1330013121011