Base | Representation |
---|---|
bin | 111101111011101111… |
… | …1111001100001100011 |
3 | 110201022002111210100201 |
4 | 1323313133321201203 |
5 | 4134341321301230 |
6 | 141033332330031 |
7 | 12415616564365 |
oct | 1736737714143 |
9 | 421262453321 |
10 | 133001353315 |
11 | 51450884316 |
12 | 21939a73917 |
13 | c70794103c |
14 | 6619d44d35 |
15 | 36d65c35ca |
hex | 1ef77f9863 |
133001353315 has 4 divisors (see below), whose sum is σ = 159601623984. Its totient is φ = 106401082648.
The previous prime is 133001353307. The next prime is 133001353321. The reversal of 133001353315 is 513353100331.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 513353100331 = 33317 ⋅15408143.
It is a cyclic number.
It is not a de Polignac number, because 133001353315 - 23 = 133001353307 is a prime.
It is a super-2 number, since 2×1330013533152 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13300135327 + ... + 13300135336.
It is an arithmetic number, because the mean of its divisors is an integer number (39900405996).
Almost surely, 2133001353315 is an apocalyptic number.
133001353315 is a deficient number, since it is larger than the sum of its proper divisors (26600270669).
133001353315 is an equidigital number, since it uses as much as digits as its factorization.
133001353315 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26600270668.
The product of its (nonzero) digits is 6075, while the sum is 28.
Adding to 133001353315 its reverse (513353100331), we get a palindrome (646354453646).
The spelling of 133001353315 in words is "one hundred thirty-three billion, one million, three hundred fifty-three thousand, three hundred fifteen".
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