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133002011113 = 373594648949
BaseRepresentation
bin111101111011110001…
…0011010000111101001
3110201022010202012200121
41323313202122013221
54134342003323423
6141033354403241
712415625304226
oct1736742320751
9421263665617
10133002011113
1151451193554
122193a130521
13c707b1157a
14661a07694d
1536d66a345d
hex1ef789a1e9

133002011113 has 4 divisors (see below), whose sum is σ = 136596660100. Its totient is φ = 129407362128.

The previous prime is 133002011101. The next prime is 133002011123. The reversal of 133002011113 is 311110200331.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 311110200331 = 744444314333.

It can be written as a sum of positive squares in 2 ways, for example, as 62274204304 + 70727806809 = 249548^2 + 265947^2 .

It is a cyclic number.

It is not a de Polignac number, because 133002011113 - 217 = 133001880041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133002011123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1797324438 + ... + 1797324511.

It is an arithmetic number, because the mean of its divisors is an integer number (34149165025).

Almost surely, 2133002011113 is an apocalyptic number.

It is an amenable number.

133002011113 is a deficient number, since it is larger than the sum of its proper divisors (3594648987).

133002011113 is an equidigital number, since it uses as much as digits as its factorization.

133002011113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3594648986.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 133002011113 its reverse (311110200331), we get a palindrome (444112211444).

The spelling of 133002011113 in words is "one hundred thirty-three billion, two million, eleven thousand, one hundred thirteen".

Divisors: 1 37 3594648949 133002011113