Base | Representation |
---|---|
bin | 1100000110001011011111… |
… | …0110010111010010100001 |
3 | 1202002111102000000020112112 |
4 | 3001202313312113102201 |
5 | 3220403010111330423 |
6 | 44142024105005105 |
7 | 2541625625055614 |
oct | 301426766272241 |
9 | 52074360006475 |
10 | 13300303230113 |
11 | 4268699487299 |
12 | 15a9830783795 |
13 | 7562a0576113 |
14 | 33da4953c17b |
15 | 180e88791a78 |
hex | c18b7d974a1 |
13300303230113 has 16 divisors (see below), whose sum is σ = 13570191835200. Its totient is φ = 13031966890560.
The previous prime is 13300303230061. The next prime is 13300303230157. The reversal of 13300303230113 is 31103230300331.
13300303230113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 13300303230113 - 222 = 13300299035809 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13300303230413) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21696623 + ... + 22301211.
It is an arithmetic number, because the mean of its divisors is an integer number (848136989700).
Almost surely, 213300303230113 is an apocalyptic number.
It is an amenable number.
13300303230113 is a deficient number, since it is larger than the sum of its proper divisors (269888605087).
13300303230113 is an equidigital number, since it uses as much as digits as its factorization.
13300303230113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 605872.
The product of its (nonzero) digits is 1458, while the sum is 23.
Adding to 13300303230113 its reverse (31103230300331), we get a palindrome (44403533530444).
The spelling of 13300303230113 in words is "thirteen trillion, three hundred billion, three hundred three million, two hundred thirty thousand, one hundred thirteen".
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