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13300313113003 = 71900044730429
BaseRepresentation
bin1100000110001011100001…
…1100000100000110101011
31202002111102200121100022111
43001202320130010012223
53220403020124104003
644142025100503151
72541626105056660
oct301427034040653
952074380540274
1013300313113003
1142686a4017474
1215a9833b4aab7
137562a2626597
1433da4a991a67
15180e89594e6d
hexc18b87041ab

13300313113003 has 4 divisors (see below), whose sum is σ = 15200357843440. Its totient is φ = 11400268382568.

The previous prime is 13300313112959. The next prime is 13300313113069. The reversal of 13300313113003 is 30031131300331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13300313113003 - 217 = 13300312981931 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13300313113093) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 950022365208 + ... + 950022365221.

It is an arithmetic number, because the mean of its divisors is an integer number (3800089460860).

Almost surely, 213300313113003 is an apocalyptic number.

13300313113003 is a deficient number, since it is larger than the sum of its proper divisors (1900044730437).

13300313113003 is an equidigital number, since it uses as much as digits as its factorization.

13300313113003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1900044730436.

The product of its (nonzero) digits is 729, while the sum is 22.

Adding to 13300313113003 its reverse (30031131300331), we get a palindrome (43331444413334).

The spelling of 13300313113003 in words is "thirteen trillion, three hundred billion, three hundred thirteen million, one hundred thirteen thousand, three".

Divisors: 1 7 1900044730429 13300313113003