133003244140003 has 4 divisors (see below), whose sum is σ = 133195723509928. Its totient is φ = 132810764770080.

The previous prime is 133003244139911. The next prime is 133003244140069. The reversal of 133003244140003 is 300041442300331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133003244140003 - 2¹⁷ = 133003244008931 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133003244147003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 96239683926 + ... + 96239685307.

It is an arithmetic number, because the mean of its divisors is an integer number (33298930877482).

Almost surely, 2^{133003244140003} is an apocalyptic number.

133003244140003 is a deficient number, since it is larger than the sum of its proper divisors (192479369925).

133003244140003 is an equidigital number, since it uses as much as digits as its factorization.

133003244140003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 192479369924.

The product of its (nonzero) digits is 10368, while the sum is 28.

Adding to 133003244140003 its reverse (300041442300331), we get a palindrome (433044686440334).

The spelling of 133003244140003 in words is "one hundred thirty-three trillion, three billion, two hundred forty-four million, one hundred forty thousand, three".