13300330114433 has 8 divisors (see below), whose sum is σ = 13311641680680. Its totient is φ = 13289023238400.

The previous prime is 13300330114429. The next prime is 13300330114451. The reversal of 13300330114433 is 33441103300331.

It can be written as a sum of positive squares in 4 ways, for example, as 8445812444224 + 4854517670209 = 2906168^2 + 2203297^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13300330114433 - 2² = 13300330114429 is a prime.

It is a super-2 number, since 2×13300330114433² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13300330114396 and 13300330114405.

It is not an unprimeable number, because it can be changed into a prime (13300330114133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4513091 + ... + 6853367.

It is an arithmetic number, because the mean of its divisors is an integer number (1663955210085).

Almost surely, 2^{13300330114433} is an apocalyptic number.

It is an amenable number.

13300330114433 is a deficient number, since it is larger than the sum of its proper divisors (11311566247).

13300330114433 is a wasteful number, since it uses less digits than its factorization.

13300330114433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2345107.

The product of its (nonzero) digits is 11664, while the sum is 29.

Adding to 13300330114433 its reverse (33441103300331), we get a palindrome (46741433414764).

The spelling of 13300330114433 in words is "thirteen trillion, three hundred billion, three hundred thirty million, one hundred fourteen thousand, four hundred thirty-three".