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1330040304203 = 13102310792631
BaseRepresentation
bin10011010110101100100…
…101000111001001001011
311201011001210111000120112
4103112230211013021023
5133242410304213303
62455002335344535
7165043432023242
oct23265445071113
94634053430515
101330040304203
11473081094386
1219592b98214b
1398564931680
14485350c5959
15248e63610d8
hex135ac94724b

1330040304203 has 4 divisors (see below), whose sum is σ = 1432351096848. Its totient is φ = 1227729511560.

The previous prime is 1330040304119. The next prime is 1330040304223. The reversal of 1330040304203 is 3024030400331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1330040304203 - 238 = 1055162397259 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1330040304223) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51155396303 + ... + 51155396328.

It is an arithmetic number, because the mean of its divisors is an integer number (358087774212).

Almost surely, 21330040304203 is an apocalyptic number.

1330040304203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1330040304203 is a deficient number, since it is larger than the sum of its proper divisors (102310792645).

1330040304203 is a wasteful number, since it uses less digits than its factorization.

1330040304203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 102310792644.

The product of its (nonzero) digits is 2592, while the sum is 23.

Adding to 1330040304203 its reverse (3024030400331), we get a palindrome (4354070704534).

The spelling of 1330040304203 in words is "one trillion, three hundred thirty billion, forty million, three hundred four thousand, two hundred three".

Divisors: 1 13 102310792631 1330040304203