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13301010013121 = 17782412353713
BaseRepresentation
bin1100000110001110000111…
…1110100001101111000001
31202002120020020221112112222
43001203201332201233001
53220410432030404441
644142222153500425
72541652266450515
oct301434176415701
952076206845488
1013301010013121
114268a21439886
1215a99a9411715
13756383b1ba0c
1433dab5360145
15180eca853d4b
hexc18e1fa1bc1

13301010013121 has 4 divisors (see below), whose sum is σ = 14083422366852. Its totient is φ = 12518597659392.

The previous prime is 13301010013037. The next prime is 13301010013169. The reversal of 13301010013121 is 12131001010331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8659954128400 + 4641055884721 = 2942780^2 + 2154311^2 .

It is a cyclic number.

It is not a de Polignac number, because 13301010013121 - 222 = 13301005818817 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (17), and also a Moran number because the ratio is a prime number: 782412353713 = 13301010013121 / (1 + 3 + 3 + 0 + 1 + 0 + 1 + 0 + 0 + 1 + 3 + 1 + 2 + 1).

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13301010013121.

It is not an unprimeable number, because it can be changed into a prime (13301010013321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 391206176840 + ... + 391206176873.

It is an arithmetic number, because the mean of its divisors is an integer number (3520855591713).

Almost surely, 213301010013121 is an apocalyptic number.

It is an amenable number.

13301010013121 is a deficient number, since it is larger than the sum of its proper divisors (782412353731).

13301010013121 is an equidigital number, since it uses as much as digits as its factorization.

13301010013121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 782412353730.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 13301010013121 its reverse (12131001010331), we get a palindrome (25432011023452).

The spelling of 13301010013121 in words is "thirteen trillion, three hundred one billion, ten million, thirteen thousand, one hundred twenty-one".

Divisors: 1 17 782412353713 13301010013121