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1330102301113 = 2358219934811
BaseRepresentation
bin10011010110110000010…
…001100111000110111001
311201011020010010210100101
4103112300101213012321
5133243022142113423
62455012432235401
7165045114005245
oct23266021470671
94634203123311
101330102301113
114731030895a3
1219594869bb61
139857472a531
144853d423425
15248eba0a7ad
hex135b04671b9

1330102301113 has 8 divisors (see below), whose sum is σ = 1388171411136. Its totient is φ = 1272053072400.

The previous prime is 1330102301057. The next prime is 1330102301137. The reversal of 1330102301113 is 3111032010331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1330102301113 - 229 = 1329565430201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1330102301153) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4833523 + ... + 5101288.

It is an arithmetic number, because the mean of its divisors is an integer number (173521426392).

Almost surely, 21330102301113 is an apocalyptic number.

It is an amenable number.

1330102301113 is a deficient number, since it is larger than the sum of its proper divisors (58069110023).

1330102301113 is an equidigital number, since it uses as much as digits as its factorization.

1330102301113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9940655.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1330102301113 its reverse (3111032010331), we get a palindrome (4441134311444).

The spelling of 1330102301113 in words is "one trillion, three hundred thirty billion, one hundred two million, three hundred one thousand, one hundred thirteen".

Divisors: 1 23 5821 133883 9934811 228500653 57830534831 1330102301113