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1330103210011 = 4013316965611
BaseRepresentation
bin10011010110110000010…
…101000101000000011011
311201011020011211222010021
4103112300111011000123
5133243022410210021
62455012503531311
7165045124512142
oct23266025050033
94634204758107
101330103210011
1147310364a454
12195948a59b37
1398574988144
144853d5bc759
15248ebb39c41
hex135b054501b

1330103210011 has 4 divisors (see below), whose sum is σ = 1333420176024. Its totient is φ = 1326786244000.

The previous prime is 1330103210003. The next prime is 1330103210021. The reversal of 1330103210011 is 1100123010331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1330103210011 - 23 = 1330103210003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1330103210021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1658482405 + ... + 1658483206.

It is an arithmetic number, because the mean of its divisors is an integer number (333355044006).

Almost surely, 21330103210011 is an apocalyptic number.

1330103210011 is a deficient number, since it is larger than the sum of its proper divisors (3316966013).

1330103210011 is an equidigital number, since it uses as much as digits as its factorization.

1330103210011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3316966012.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1330103210011 its reverse (1100123010331), we get a palindrome (2430226220342).

The spelling of 1330103210011 in words is "one trillion, three hundred thirty billion, one hundred three million, two hundred ten thousand, eleven".

Divisors: 1 401 3316965611 1330103210011