Base | Representation |
---|---|
bin | 1100000110001110010111… |
… | …1111110110101000110001 |
3 | 1202002120101221212200122110 |
4 | 3001203211333312220301 |
5 | 3220411101313012440 |
6 | 44142233003355533 |
7 | 2541654046022202 |
oct | 301434577665061 |
9 | 52076357780573 |
10 | 13301077469745 |
11 | 4268a56522a5a |
12 | 15a9a07b22ba9 |
13 | 756394aa9990 |
14 | 33dac02bd5a9 |
15 | 180ed172b080 |
hex | c18e5ff6a31 |
13301077469745 has 16 divisors (see below), whose sum is σ = 22918779640512. Its totient is φ = 6548222754240.
The previous prime is 13301077469737. The next prime is 13301077469749. The reversal of 13301077469745 is 54796477010331.
It is not a de Polignac number, because 13301077469745 - 23 = 13301077469737 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (13301077469749) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 34105326651 + ... + 34105327040.
It is an arithmetic number, because the mean of its divisors is an integer number (1432423727532).
Almost surely, 213301077469745 is an apocalyptic number.
13301077469745 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13301077469745 is a deficient number, since it is larger than the sum of its proper divisors (9617702170767).
13301077469745 is a wasteful number, since it uses less digits than its factorization.
13301077469745 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 68210653712.
The product of its (nonzero) digits is 13335840, while the sum is 57.
The spelling of 13301077469745 in words is "thirteen trillion, three hundred one billion, seventy-seven million, four hundred sixty-nine thousand, seven hundred forty-five".
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