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1330110300201 = 3443370100067
BaseRepresentation
bin10011010110110000110…
…000001000000000101001
311201011020200012012000220
4103112300300020000221
5133243031214101301
62455013315520253
7165045242002224
oct23266060100051
94634220165026
101330110300201
11473107652411
1219594b2b9089
139857629b417
14485405065bb
15248ec58a936
hex135b0c08029

1330110300201 has 4 divisors (see below), whose sum is σ = 1773480400272. Its totient is φ = 886740200132.

The previous prime is 1330110300163. The next prime is 1330110300251. The reversal of 1330110300201 is 1020030110331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1330110300201 - 213 = 1330110292009 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1330110300251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 221685050031 + ... + 221685050036.

It is an arithmetic number, because the mean of its divisors is an integer number (443370100068).

Almost surely, 21330110300201 is an apocalyptic number.

It is an amenable number.

1330110300201 is a deficient number, since it is larger than the sum of its proper divisors (443370100071).

1330110300201 is an equidigital number, since it uses as much as digits as its factorization.

1330110300201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 443370100070.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 1330110300201 its reverse (1020030110331), we get a palindrome (2350140410532).

The spelling of 1330110300201 in words is "one trillion, three hundred thirty billion, one hundred ten million, three hundred thousand, two hundred one".

Divisors: 1 3 443370100067 1330110300201