133011030113 has 8 divisors (see below), whose sum is σ = 143249265600. Its totient is φ = 122773740048.

The previous prime is 133011030083. The next prime is 133011030133. The reversal of 133011030113 is 311030110331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 133011030113 - 2⁸ = 133011029857 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133011030091 and 133011030100.

It is not an unprimeable number, because it can be changed into a prime (133011030133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 70628 + ... + 520586.

It is an arithmetic number, because the mean of its divisors is an integer number (17906158200).

Almost surely, 2^133011030113 is an apocalyptic number.

133011030113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

133011030113 is a deficient number, since it is larger than the sum of its proper divisors (10238235487).

133011030113 is a wasteful number, since it uses less digits than its factorization.

133011030113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 472711.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 133011030113 its reverse (311030110331), we get a palindrome (444041140444).

The spelling of 133011030113 in words is "one hundred thirty-three billion, eleven million, thirty thousand, one hundred thirteen".