13301103014321 has 4 divisors (see below), whose sum is σ = 13301167673700. Its totient is φ = 13301038354944.

The previous prime is 13301103014281. The next prime is 13301103014387. The reversal of 13301103014321 is 12341030110331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 12425448750625 + 875654263696 = 3524975^2 + 935764^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13301103014321 is a prime.

It is a super-3 number, since 3×13301103014321³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13301103014621) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32020136 + ... + 32432873.

It is an arithmetic number, because the mean of its divisors is an integer number (3325291918425).

Almost surely, 2^{13301103014321} is an apocalyptic number.

It is an amenable number.

13301103014321 is a deficient number, since it is larger than the sum of its proper divisors (64659379).

13301103014321 is an equidigital number, since it uses as much as digits as its factorization.

13301103014321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 64659378.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 13301103014321 its reverse (12341030110331), we get a palindrome (25642133124652).

The spelling of 13301103014321 in words is "thirteen trillion, three hundred one billion, one hundred three million, fourteen thousand, three hundred twenty-one".