Base | Representation |
---|---|
bin | 1100000110001110100100… |
… | …1111111100100101001001 |
3 | 1202002120112202112010120210 |
4 | 3001203221033330211021 |
5 | 3220411204244120131 |
6 | 44142242232511333 |
7 | 2541655310501025 |
oct | 301435117744511 |
9 | 52076482463523 |
10 | 13301132020041 |
11 | 4268a842a1448 |
12 | 15a9a2224b549 |
13 | 7563a3199268 |
14 | 33dac763d385 |
15 | 180ed6404146 |
hex | c18e93fc949 |
13301132020041 has 16 divisors (see below), whose sum is σ = 18405003692160. Its totient is φ = 8534294670720.
The previous prime is 13301132019977. The next prime is 13301132020049. The reversal of 13301132020041 is 14002023110331.
13301132020041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13301132020041 - 26 = 13301132019977 is a prime.
It is a super-2 number, since 2×133011320200412 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13301132020049) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 244200525 + ... + 244254986.
It is an arithmetic number, because the mean of its divisors is an integer number (1150312730760).
Almost surely, 213301132020041 is an apocalyptic number.
It is an amenable number.
13301132020041 is a deficient number, since it is larger than the sum of its proper divisors (5103871672119).
13301132020041 is a wasteful number, since it uses less digits than its factorization.
13301132020041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 488455856.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 13301132020041 its reverse (14002023110331), we get a palindrome (27303155130372).
The spelling of 13301132020041 in words is "thirteen trillion, three hundred one billion, one hundred thirty-two million, twenty thousand, forty-one".
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