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133011420043 = 177824201179
BaseRepresentation
bin111101111100000011…
…0010011001110001011
3110201022210110020022111
41323320012103032023
54134401410420133
6141034332203151
712416101262425
oct1737006231613
9421283406274
10133011420043
115145652a627
12219413094b7
13c709a57098
14661b405815
1536d74111cd
hex1ef819338b

133011420043 has 4 divisors (see below), whose sum is σ = 140835621240. Its totient is φ = 125187218848.

The previous prime is 133011419999. The next prime is 133011420067. The reversal of 133011420043 is 340024110331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133011420043 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133011419996 and 133011420023.

It is not an unprimeable number, because it can be changed into a prime (133011420643) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3912100573 + ... + 3912100606.

It is an arithmetic number, because the mean of its divisors is an integer number (35208905310).

Almost surely, 2133011420043 is an apocalyptic number.

133011420043 is a deficient number, since it is larger than the sum of its proper divisors (7824201197).

133011420043 is an equidigital number, since it uses as much as digits as its factorization.

133011420043 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7824201196.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 133011420043 its reverse (340024110331), we get a palindrome (473035530374).

The spelling of 133011420043 in words is "one hundred thirty-three billion, eleven million, four hundred twenty thousand, forty-three".

Divisors: 1 17 7824201179 133011420043