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13301201122003 = 23578313092261
BaseRepresentation
bin1100000110001110110101…
…0111100011001011010011
31202002120201120112212122201
43001203231113203023103
53220411324441401003
644142253141544031
72541660110034334
oct301435527431323
952076646485581
1013301201122003
11426900a2a9803
1215a9a41415017
137563b45b20b2
1433dad28aa28b
15180edc503b1d
hexc18ed5e32d3

13301201122003 has 4 divisors (see below), whose sum is σ = 13879514214288. Its totient is φ = 12722888029720.

The previous prime is 13301201121997. The next prime is 13301201122019. The reversal of 13301201122003 is 30022110210331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13301201122003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13301201122063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 289156546108 + ... + 289156546153.

It is an arithmetic number, because the mean of its divisors is an integer number (3469878553572).

Almost surely, 213301201122003 is an apocalyptic number.

13301201122003 is a deficient number, since it is larger than the sum of its proper divisors (578313092285).

13301201122003 is an equidigital number, since it uses as much as digits as its factorization.

13301201122003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 578313092284.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 13301201122003 its reverse (30022110210331), we get a palindrome (43323311332334).

The spelling of 13301201122003 in words is "thirteen trillion, three hundred one billion, two hundred one million, one hundred twenty-two thousand, three".

Divisors: 1 23 578313092261 13301201122003