133012025133513 has 4 divisors (see below), whose sum is σ = 177349366844688. Its totient is φ = 88674683422340.

The previous prime is 133012025133467. The next prime is 133012025133551. The reversal of 133012025133513 is 315331520210331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133012025133513 - 2³² = 133007730166217 is a prime.

It is not an unprimeable number, because it can be changed into a prime (133012025133413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22168670855583 + ... + 22168670855588.

It is an arithmetic number, because the mean of its divisors is an integer number (44337341711172).

Almost surely, 2^{133012025133513} is an apocalyptic number.

It is an amenable number.

133012025133513 is a deficient number, since it is larger than the sum of its proper divisors (44337341711175).

133012025133513 is an equidigital number, since it uses as much as digits as its factorization.

133012025133513 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44337341711174.

The product of its (nonzero) digits is 24300, while the sum is 33.

Adding to 133012025133513 its reverse (315331520210331), we get a palindrome (448343545343844).

The spelling of 133012025133513 in words is "one hundred thirty-three trillion, twelve billion, twenty-five million, one hundred thirty-three thousand, five hundred thirteen".