13301300113 has 4 divisors (see below), whose sum is σ = 14001368560. Its totient is φ = 12601231668.

The previous prime is 13301300101. The next prime is 13301300137. The reversal of 13301300113 is 31100310331.

13301300113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31100310331 = 166151 ⋅187181.

It is a cyclic number.

It is not a de Polignac number, because 13301300113 - 2¹³ = 13301291921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13301300183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 350034195 + ... + 350034232.

It is an arithmetic number, because the mean of its divisors is an integer number (3500342140).

Almost surely, 2^13301300113 is an apocalyptic number.

It is an amenable number.

13301300113 is a deficient number, since it is larger than the sum of its proper divisors (700068447).

13301300113 is an equidigital number, since it uses as much as digits as its factorization.

13301300113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 700068446.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 13301300113 its reverse (31100310331), we get a palindrome (44401610444).

The spelling of 13301300113 in words is "thirteen billion, three hundred one million, three hundred thousand, one hundred thirteen".