Base | Representation |
---|---|
bin | 10011010110110010000… |
… | …111110111111011100011 |
3 | 11201011022021110211221211 |
4 | 103112302013313323203 |
5 | 133243103111144021 |
6 | 2455015500530551 |
7 | 165045641345632 |
oct | 23266207677343 |
9 | 4634267424854 |
10 | 1330133303011 |
11 | 4731196337a7 |
12 | 195956b50a57 |
13 | 9857ac93556 |
14 | 485435b3519 |
15 | 248ee5d13e1 |
hex | 135b21f7ee3 |
1330133303011 has 4 divisors (see below), whose sum is σ = 1330160788800. Its totient is φ = 1330105817224.
The previous prime is 1330133302991. The next prime is 1330133303039. The reversal of 1330133303011 is 1103033310331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1330133303011 - 221 = 1330131205859 is a prime.
It is a super-2 number, since 2×13301333030112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1330133300011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13670176 + ... + 13767133.
It is an arithmetic number, because the mean of its divisors is an integer number (332540197200).
Almost surely, 21330133303011 is an apocalyptic number.
1330133303011 is a deficient number, since it is larger than the sum of its proper divisors (27485789).
1330133303011 is an equidigital number, since it uses as much as digits as its factorization.
1330133303011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 27485788.
The product of its (nonzero) digits is 729, while the sum is 22.
Adding to 1330133303011 its reverse (1103033310331), we get a palindrome (2433166613342).
The spelling of 1330133303011 in words is "one trillion, three hundred thirty billion, one hundred thirty-three million, three hundred three thousand, eleven".
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