13301404431401 has 4 divisors (see below), whose sum is σ = 13330510349652. Its totient is φ = 13272298513152.

The previous prime is 13301404431373. The next prime is 13301404431409. The reversal of 13301404431401 is 10413440410331.

13301404431401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5982431701801 + 7318972729600 = 2445901^2 + 2705360^2 .

It is a cyclic number.

It is not a de Polignac number, because 13301404431401 - 2¹⁴ = 13301404415017 is a prime.

It is a super-2 number, since 2×13301404431401² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13301404431409) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14552958440 + ... + 14552959353.

It is an arithmetic number, because the mean of its divisors is an integer number (3332627587413).

Almost surely, 2^{13301404431401} is an apocalyptic number.

It is an amenable number.

13301404431401 is a deficient number, since it is larger than the sum of its proper divisors (29105918251).

13301404431401 is an equidigital number, since it uses as much as digits as its factorization.

13301404431401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29105918250.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 13301404431401 its reverse (10413440410331), we get a palindrome (23714844841732).

The spelling of 13301404431401 in words is "thirteen trillion, three hundred one billion, four hundred four million, four hundred thirty-one thousand, four hundred one".