13301434232241 has 16 divisors (see below), whose sum is σ = 18215534498304. Its totient is φ = 8627503601664.

The previous prime is 13301434232239. The next prime is 13301434232269. The reversal of 13301434232241 is 14223243410331.

13301434232241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 13301434232241 - 2¹ = 13301434232239 is a prime.

It is a super-3 number, since 3×13301434232241³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13301434232221) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1024321 + ... + 5258526.

It is an arithmetic number, because the mean of its divisors is an integer number (1138470906144).

Almost surely, 2^{13301434232241} is an apocalyptic number.

It is an amenable number.

13301434232241 is a deficient number, since it is larger than the sum of its proper divisors (4914100266063).

13301434232241 is a wasteful number, since it uses less digits than its factorization.

13301434232241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6301960.

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 13301434232241 its reverse (14223243410331), we get a palindrome (27524677642572).

The spelling of 13301434232241 in words is "thirteen trillion, three hundred one billion, four hundred thirty-four million, two hundred thirty-two thousand, two hundred forty-one".