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1330144243003 = 1970007591737
BaseRepresentation
bin10011010110110010110…
…001100110110100111011
311201011100001001122210201
4103112302301212310323
5133243113411234003
62455020531223031
7165046133341642
oct23266261466473
94634301048721
101330144243003
11473124826114
1219595a747a77
1398580323c14
1448544c20359
1524900542b1d
hex135b2c66d3b

1330144243003 has 4 divisors (see below), whose sum is σ = 1400151834760. Its totient is φ = 1260136651248.

The previous prime is 1330144242979. The next prime is 1330144243007. The reversal of 1330144243003 is 3003424410331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1330144243003 - 25 = 1330144242971 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1330144243007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35003795850 + ... + 35003795887.

It is an arithmetic number, because the mean of its divisors is an integer number (350037958690).

Almost surely, 21330144243003 is an apocalyptic number.

1330144243003 is a deficient number, since it is larger than the sum of its proper divisors (70007591757).

1330144243003 is an equidigital number, since it uses as much as digits as its factorization.

1330144243003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70007591756.

The product of its (nonzero) digits is 10368, while the sum is 28.

Adding to 1330144243003 its reverse (3003424410331), we get a palindrome (4333568653334).

The spelling of 1330144243003 in words is "one trillion, three hundred thirty billion, one hundred forty-four million, two hundred forty-three thousand, three".

Divisors: 1 19 70007591737 1330144243003