Base | Representation |
---|---|
bin | 111101111100001001… |
… | …1100001101101010011 |
3 | 110201100000222101102121 |
4 | 1323320103201231103 |
5 | 4134403302343001 |
6 | 141034534355111 |
7 | 12416142613051 |
oct | 1737023415523 |
9 | 421300871377 |
10 | 133014887251 |
11 | 51458488594 |
12 | 219424bba97 |
13 | c70a69c29c |
14 | 661ba691d1 |
15 | 36d78986a1 |
hex | 1ef84e1b53 |
133014887251 has 4 divisors (see below), whose sum is σ = 133704083752. Its totient is φ = 132325690752.
The previous prime is 133014887219. The next prime is 133014887293. The reversal of 133014887251 is 152788410331.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 152788410331 = 66109 ⋅2311159.
It is a cyclic number.
It is not a de Polignac number, because 133014887251 - 25 = 133014887219 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 133014887198 and 133014887207.
It is not an unprimeable number, because it can be changed into a prime (133014837251) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 344597961 + ... + 344598346.
It is an arithmetic number, because the mean of its divisors is an integer number (33426020938).
Almost surely, 2133014887251 is an apocalyptic number.
133014887251 is a deficient number, since it is larger than the sum of its proper divisors (689196501).
133014887251 is an equidigital number, since it uses as much as digits as its factorization.
133014887251 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 689196500.
The product of its (nonzero) digits is 161280, while the sum is 43.
The spelling of 133014887251 in words is "one hundred thirty-three billion, fourteen million, eight hundred eighty-seven thousand, two hundred fifty-one".
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