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133020404025441 = 373682389022293
BaseRepresentation
bin11110001111101100111001…
…111011100000100001100001
3122102222121220200001110011220
4132033230321323200201201
5114413401241412303231
61150524421402325253
740006256421261312
oct3617547173404141
9572877820043156
10133020404025441
1139425700268249
1212b042b41b9829
13592ba023b060a
1424bc316cac609
15105a275264896
hex78fb39ee0861

133020404025441 has 16 divisors (see below), whose sum is σ = 179816487739776. Its totient is φ = 87452650947456.

The previous prime is 133020404025323. The next prime is 133020404025461. The reversal of 133020404025441 is 144520404020331.

It is not a de Polignac number, because 133020404025441 - 239 = 132470648211553 is a prime.

It is not an unprimeable number, because it can be changed into a prime (133020404025461) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 43016910 + ... + 46005383.

It is an arithmetic number, because the mean of its divisors is an integer number (11238530483736).

Almost surely, 2133020404025441 is an apocalyptic number.

It is an amenable number.

133020404025441 is a deficient number, since it is larger than the sum of its proper divisors (46796083714335).

133020404025441 is an equidigital number, since it uses as much as digits as its factorization.

133020404025441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 89029192.

The product of its (nonzero) digits is 46080, while the sum is 33.

Adding to 133020404025441 its reverse (144520404020331), we get a palindrome (277540808045772).

The spelling of 133020404025441 in words is "one hundred thirty-three trillion, twenty billion, four hundred four million, twenty-five thousand, four hundred forty-one".

Divisors: 1 3 73 219 6823 20469 498079 1494237 89022293 267066879 6498627389 19495882167 607399105139 1822197315417 44340134675147 133020404025441