Base | Representation |
---|---|
bin | 11110001111101100111001… |
… | …111011100000100001100001 |
3 | 122102222121220200001110011220 |
4 | 132033230321323200201201 |
5 | 114413401241412303231 |
6 | 1150524421402325253 |
7 | 40006256421261312 |
oct | 3617547173404141 |
9 | 572877820043156 |
10 | 133020404025441 |
11 | 39425700268249 |
12 | 12b042b41b9829 |
13 | 592ba023b060a |
14 | 24bc316cac609 |
15 | 105a275264896 |
hex | 78fb39ee0861 |
133020404025441 has 16 divisors (see below), whose sum is σ = 179816487739776. Its totient is φ = 87452650947456.
The previous prime is 133020404025323. The next prime is 133020404025461. The reversal of 133020404025441 is 144520404020331.
It is not a de Polignac number, because 133020404025441 - 239 = 132470648211553 is a prime.
It is not an unprimeable number, because it can be changed into a prime (133020404025461) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 43016910 + ... + 46005383.
It is an arithmetic number, because the mean of its divisors is an integer number (11238530483736).
Almost surely, 2133020404025441 is an apocalyptic number.
It is an amenable number.
133020404025441 is a deficient number, since it is larger than the sum of its proper divisors (46796083714335).
133020404025441 is an equidigital number, since it uses as much as digits as its factorization.
133020404025441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 89029192.
The product of its (nonzero) digits is 46080, while the sum is 33.
Adding to 133020404025441 its reverse (144520404020331), we get a palindrome (277540808045772).
The spelling of 133020404025441 in words is "one hundred thirty-three trillion, twenty billion, four hundred four million, twenty-five thousand, four hundred forty-one".
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