13302101113 has 4 divisors (see below), whose sum is σ = 15202401280. Its totient is φ = 11401800948.

The previous prime is 13302101017. The next prime is 13302101143. The reversal of 13302101113 is 31110120331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31110120331 = 37 ⋅840814063.

It is a cyclic number.

It is not a de Polignac number, because 13302101113 - 2⁹ = 13302100601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13302101143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 950150073 + ... + 950150086.

It is an arithmetic number, because the mean of its divisors is an integer number (3800600320).

Almost surely, 2^13302101113 is an apocalyptic number.

It is an amenable number.

13302101113 is a deficient number, since it is larger than the sum of its proper divisors (1900300167).

13302101113 is an equidigital number, since it uses as much as digits as its factorization.

13302101113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1900300166.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 13302101113 its reverse (31110120331), we get a palindrome (44412221444).

The spelling of 13302101113 in words is "thirteen billion, three hundred two million, one hundred one thousand, one hundred thirteen".