Base | Representation |
---|---|
bin | 1100000110010010001110… |
… | …0110110110100010011011 |
3 | 1202002200001222211201002110 |
4 | 3001210203212312202123 |
5 | 3220420210420300011 |
6 | 44142523330003403 |
7 | 2542021466533464 |
oct | 301444346664233 |
9 | 52080058751073 |
10 | 13302111103131 |
11 | 4269436a29024 |
12 | 15aa056116563 |
13 | 7564cac91876 |
14 | 33db7b6a3d6b |
15 | 181042352ba6 |
hex | c19239b689b |
13302111103131 has 8 divisors (see below), whose sum is σ = 17736213297424. Its totient is φ = 8868041488800.
The previous prime is 13302111103103. The next prime is 13302111103159. The reversal of 13302111103131 is 13130111120331.
It is an interprime number because it is at equal distance from previous prime (13302111103103) and next prime (13302111103159).
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13302111103131 - 230 = 13301037361307 is a prime.
It is a super-2 number, since 2×133021111031312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13302111103098 and 13302111103107.
It is not an unprimeable number, because it can be changed into a prime (13302111103181) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7175836 + ... + 8837241.
It is an arithmetic number, because the mean of its divisors is an integer number (2217026662178).
Almost surely, 213302111103131 is an apocalyptic number.
13302111103131 is a deficient number, since it is larger than the sum of its proper divisors (4434102194293).
13302111103131 is a wasteful number, since it uses less digits than its factorization.
13302111103131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16289981.
The product of its (nonzero) digits is 162, while the sum is 21.
Adding to 13302111103131 its reverse (13130111120331), we get a palindrome (26432222223462).
It can be divided in two parts, 1330211 and 1103131, that added together give a palindrome (2433342).
The spelling of 13302111103131 in words is "thirteen trillion, three hundred two billion, one hundred eleven million, one hundred three thousand, one hundred thirty-one".
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