1330213111001 has 4 divisors (see below), whose sum is σ = 1339022469504. Its totient is φ = 1321403752500.

The previous prime is 1330213110913. The next prime is 1330213111033. The reversal of 1330213111001 is 1001113120331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1330213111001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1330213111901) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4404679025 + ... + 4404679326.

It is an arithmetic number, because the mean of its divisors is an integer number (334755617376).

Almost surely, 2^{1330213111001} is an apocalyptic number.

It is an amenable number.

1330213111001 is a deficient number, since it is larger than the sum of its proper divisors (8809358503).

1330213111001 is an equidigital number, since it uses as much as digits as its factorization.

1330213111001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8809358502.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1330213111001 its reverse (1001113120331), we get a palindrome (2331326231332).

The spelling of 1330213111001 in words is "one trillion, three hundred thirty billion, two hundred thirteen million, one hundred eleven thousand, one".