Search a number
-
+
133023000201115 = 529917400001387
BaseRepresentation
bin11110001111101111010100…
…101011001000011110011011
3122102222212121121012211200111
4132033233110223020132123
5114413422101022413430
61150525531143345151
740006410644353513
oct3617572453103633
9572885547184614
10133023000201115
1139426812790482
1212b048b97521b7
13592c02721493b
1424bc4c19d6843
15105a37813bc2a
hex78fbd4ac879b

133023000201115 has 8 divisors (see below), whose sum is σ = 165132000249840. Its totient is φ = 102748800155232.

The previous prime is 133023000201109. The next prime is 133023000201139. The reversal of 133023000201115 is 511102000320331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133023000201115 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 458700000549 + ... + 458700000838.

It is an arithmetic number, because the mean of its divisors is an integer number (20641500031230).

Almost surely, 2133023000201115 is an apocalyptic number.

133023000201115 is a deficient number, since it is larger than the sum of its proper divisors (32109000048725).

133023000201115 is an equidigital number, since it uses as much as digits as its factorization.

133023000201115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 917400001421.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 133023000201115 its reverse (511102000320331), we get a palindrome (644125000521446).

The spelling of 133023000201115 in words is "one hundred thirty-three trillion, twenty-three billion, two hundred one thousand, one hundred fifteen".

Divisors: 1 5 29 145 917400001387 4587000006935 26604600040223 133023000201115