Base | Representation |
---|---|
bin | 10011010110110111111… |
… | …000111010000110000011 |
3 | 11201011120000111202021210 |
4 | 103112313320322012003 |
5 | 133243302342334021 |
6 | 2455033234221203 |
7 | 165051224542512 |
oct | 23266770720603 |
9 | 4634500452253 |
10 | 1330230043011 |
11 | 4731691a8a11 |
12 | 195983424803 |
13 | 9859503525c |
14 | 48552396679 |
15 | 24907d3ee76 |
hex | 135b7e3a183 |
1330230043011 has 8 divisors (see below), whose sum is σ = 1773844122960. Its totient is φ = 886717995872.
The previous prime is 1330230043001. The next prime is 1330230043027. The reversal of 1330230043011 is 1103400320331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1330230043011 - 221 = 1330227945859 is a prime.
It is a super-2 number, since 2×13302300430112 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1330230043001) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25477776 + ... + 25529933.
It is an arithmetic number, because the mean of its divisors is an integer number (221730515370).
Almost surely, 21330230043011 is an apocalyptic number.
1330230043011 is a deficient number, since it is larger than the sum of its proper divisors (443614079949).
1330230043011 is an equidigital number, since it uses as much as digits as its factorization.
1330230043011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51016405.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 1330230043011 its reverse (1103400320331), we get a palindrome (2433630363342).
The spelling of 1330230043011 in words is "one trillion, three hundred thirty billion, two hundred thirty million, forty-three thousand, eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •