Base | Representation |
---|---|
bin | 111101111100011010… |
… | …0000100111010001001 |
3 | 110201100122000220012212 |
4 | 1323320310010322021 |
5 | 4134412443420131 |
6 | 141035441314505 |
7 | 12416305262021 |
oct | 1737064047211 |
9 | 421318026185 |
10 | 133023420041 |
11 | 51462286386 |
12 | 21945335a35 |
13 | c70c399085 |
14 | 661cc4aa81 |
15 | 36d84d1a2b |
hex | 1ef8d04e89 |
133023420041 has 8 divisors (see below), whose sum is σ = 135752185800. Its totient is φ = 130322079360.
The previous prime is 133023419987. The next prime is 133023420067. The reversal of 133023420041 is 140024320331.
It can be written as a sum of positive squares in 4 ways, for example, as 15805518400 + 117217901641 = 125720^2 + 342371^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133023420041 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 133023419989 and 133023420016.
It is not an unprimeable number, because it can be changed into a prime (133023423041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6846470 + ... + 6865871.
It is an arithmetic number, because the mean of its divisors is an integer number (16969023225).
Almost surely, 2133023420041 is an apocalyptic number.
It is an amenable number.
133023420041 is a deficient number, since it is larger than the sum of its proper divisors (2728765759).
133023420041 is a wasteful number, since it uses less digits than its factorization.
133023420041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13712539.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 133023420041 its reverse (140024320331), we get a palindrome (273047740372).
It can be divided in two parts, 13302 and 3420041, that added together give a palindrome (3433343).
The spelling of 133023420041 in words is "one hundred thirty-three billion, twenty-three million, four hundred twenty thousand, forty-one".
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