133024211021441 has 4 divisors (see below), whose sum is σ = 133024264804800. Its totient is φ = 133024157238084.

The previous prime is 133024211021413. The next prime is 133024211021459. The reversal of 133024211021441 is 144120112420331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-133024211021441 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (133024211021941) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22993301 + ... + 28191138.

It is an arithmetic number, because the mean of its divisors is an integer number (33256066201200).

Almost surely, 2^{133024211021441} is an apocalyptic number.

It is an amenable number.

133024211021441 is a deficient number, since it is larger than the sum of its proper divisors (53783359).

133024211021441 is an equidigital number, since it uses as much as digits as its factorization.

133024211021441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 53783358.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 133024211021441 its reverse (144120112420331), we get a palindrome (277144323441772).

The spelling of 133024211021441 in words is "one hundred thirty-three trillion, twenty-four billion, two hundred eleven million, twenty-one thousand, four hundred forty-one".