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13302440300003 = 101131707329703
BaseRepresentation
bin1100000110010011011100…
…1110101000110111100011
31202002200220221021122022012
43001210313032220313203
53220421344204100003
644143020125503135
72542032604625231
oct301446716506743
952080827248265
1013302440300003
114269595834558
1215aa128411aab
13756551242c0a
1433dbad2b7951
151810611cc8d8
hexc19373a8de3

13302440300003 has 4 divisors (see below), whose sum is σ = 13434147629808. Its totient is φ = 13170732970200.

The previous prime is 13302440299969. The next prime is 13302440300047. The reversal of 13302440300003 is 30000304420331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13302440300003 - 28 = 13302440299747 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13302440303003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65853664751 + ... + 65853664952.

It is an arithmetic number, because the mean of its divisors is an integer number (3358536907452).

Almost surely, 213302440300003 is an apocalyptic number.

13302440300003 is a deficient number, since it is larger than the sum of its proper divisors (131707329805).

13302440300003 is a wasteful number, since it uses less digits than its factorization.

13302440300003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 131707329804.

The product of its (nonzero) digits is 2592, while the sum is 23.

Adding to 13302440300003 its reverse (30000304420331), we get a palindrome (43302744720334).

The spelling of 13302440300003 in words is "thirteen trillion, three hundred two billion, four hundred forty million, three hundred thousand, three".

Divisors: 1 101 131707329703 13302440300003