Base | Representation |
---|---|
bin | 1100000110010011011100… |
… | …1110101000110111100011 |
3 | 1202002200220221021122022012 |
4 | 3001210313032220313203 |
5 | 3220421344204100003 |
6 | 44143020125503135 |
7 | 2542032604625231 |
oct | 301446716506743 |
9 | 52080827248265 |
10 | 13302440300003 |
11 | 4269595834558 |
12 | 15aa128411aab |
13 | 756551242c0a |
14 | 33dbad2b7951 |
15 | 1810611cc8d8 |
hex | c19373a8de3 |
13302440300003 has 4 divisors (see below), whose sum is σ = 13434147629808. Its totient is φ = 13170732970200.
The previous prime is 13302440299969. The next prime is 13302440300047. The reversal of 13302440300003 is 30000304420331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13302440300003 - 28 = 13302440299747 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13302440303003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65853664751 + ... + 65853664952.
It is an arithmetic number, because the mean of its divisors is an integer number (3358536907452).
Almost surely, 213302440300003 is an apocalyptic number.
13302440300003 is a deficient number, since it is larger than the sum of its proper divisors (131707329805).
13302440300003 is a wasteful number, since it uses less digits than its factorization.
13302440300003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 131707329804.
The product of its (nonzero) digits is 2592, while the sum is 23.
Adding to 13302440300003 its reverse (30000304420331), we get a palindrome (43302744720334).
The spelling of 13302440300003 in words is "thirteen trillion, three hundred two billion, four hundred forty million, three hundred thousand, three".
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