Base | Representation |
---|---|
bin | 11110001111110010001010… |
… | …011111001011010100011001 |
3 | 122110000011111011221010000210 |
4 | 132033302022133023110121 |
5 | 114413444322413122340 |
6 | 1150531153550321333 |
7 | 40006546353553503 |
oct | 3617621237132431 |
9 | 573004434833023 |
10 | 133026050520345 |
11 | 3942803859a464 |
12 | 12b0540b1b9249 |
13 | 592c3c2166968 |
14 | 24bc6d0b7ad73 |
15 | 105a4a5d20180 |
hex | 78fc8a7cb519 |
133026050520345 has 8 divisors (see below), whose sum is σ = 212841680832576. Its totient is φ = 70947226944176.
The previous prime is 133026050520313. The next prime is 133026050520359. The reversal of 133026050520345 is 543025050620331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 133026050520345 - 25 = 133026050520313 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4434201683997 + ... + 4434201684026.
It is an arithmetic number, because the mean of its divisors is an integer number (26605210104072).
Almost surely, 2133026050520345 is an apocalyptic number.
133026050520345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
133026050520345 is a deficient number, since it is larger than the sum of its proper divisors (79815630312231).
133026050520345 is an equidigital number, since it uses as much as digits as its factorization.
133026050520345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8868403368031.
The product of its (nonzero) digits is 324000, while the sum is 39.
The spelling of 133026050520345 in words is "one hundred thirty-three trillion, twenty-six billion, fifty million, five hundred twenty thousand, three hundred forty-five".
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