1330300113 has 4 divisors (see below), whose sum is σ = 1773733488. Its totient is φ = 886866740.

The previous prime is 1330300007. The next prime is 1330300129. The reversal of 1330300113 is 3110030331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3110030331 = 3 ⋅1036676777.

It is a cyclic number.

It is not a de Polignac number, because 1330300113 - 2⁸ = 1330299857 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1330300092 and 1330300101.

It is not an unprimeable number, because it can be changed into a prime (1330300163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 221716683 + ... + 221716688.

It is an arithmetic number, because the mean of its divisors is an integer number (443433372).

Almost surely, 2^1330300113 is an apocalyptic number.

It is an amenable number.

1330300113 is a deficient number, since it is larger than the sum of its proper divisors (443433375).

1330300113 is an equidigital number, since it uses as much as digits as its factorization.

1330300113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 443433374.

The product of its (nonzero) digits is 81, while the sum is 15.

The square root of 1330300113 is about 36473.2794385150. The cubic root of 1330300113 is about 1099.8071598592.

Adding to 1330300113 its reverse (3110030331), we get a palindrome (4440330444).

The spelling of 1330300113 in words is "one billion, three hundred thirty million, three hundred thousand, one hundred thirteen".