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1330305300131 = 8531559560727
BaseRepresentation
bin10011010110111100010…
…111111111011010100011
311201011202021010012122112
4103112330113333122203
5133243431124101011
62455044523225535
7165053130323153
oct23267427773243
94634667105575
101330305300131
114731a772a785
121959a46782ab
13985a77c48b2
144855c386763
152490e75858b
hex135bc5ff6a3

1330305300131 has 4 divisors (see below), whose sum is σ = 1331864861712. Its totient is φ = 1328745738552.

The previous prime is 1330305300127. The next prime is 1330305300139. The reversal of 1330305300131 is 1310035030331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1330305300131 - 22 = 1330305300127 is a prime.

It is a super-2 number, since 2×13303053001312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1330305300097 and 1330305300106.

It is not an unprimeable number, because it can be changed into a prime (1330305300139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 779779511 + ... + 779781216.

It is an arithmetic number, because the mean of its divisors is an integer number (332966215428).

Almost surely, 21330305300131 is an apocalyptic number.

1330305300131 is a deficient number, since it is larger than the sum of its proper divisors (1559561581).

1330305300131 is an equidigital number, since it uses as much as digits as its factorization.

1330305300131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1559561580.

The product of its (nonzero) digits is 1215, while the sum is 23.

The spelling of 1330305300131 in words is "one trillion, three hundred thirty billion, three hundred five million, three hundred thousand, one hundred thirty-one".

Divisors: 1 853 1559560727 1330305300131