Base | Representation |
---|---|
bin | 10011010110111100101… |
… | …010011011000110100011 |
3 | 11201011202121012200220111 |
4 | 103112330222123012203 |
5 | 133243433343212011 |
6 | 2455045214552151 |
7 | 165053216356501 |
oct | 23267452330643 |
9 | 4634677180814 |
10 | 1330310132131 |
11 | 4731aa430072 |
12 | 1959a6208657 |
13 | 985a87c7076 |
14 | 4855cc83671 |
15 | 2490edb0121 |
hex | 135bca9b1a3 |
1330310132131 has 4 divisors (see below), whose sum is σ = 1330313043312. Its totient is φ = 1330307220952.
The previous prime is 1330310132059. The next prime is 1330310132171. The reversal of 1330310132131 is 1312310130331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1330310132131 - 237 = 1192871178659 is a prime.
It is a super-2 number, since 2×13303101321312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1330310132171) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 604111 + ... + 1739416.
It is an arithmetic number, because the mean of its divisors is an integer number (332578260828).
Almost surely, 21330310132131 is an apocalyptic number.
1330310132131 is a deficient number, since it is larger than the sum of its proper divisors (2911181).
1330310132131 is an equidigital number, since it uses as much as digits as its factorization.
1330310132131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2911180.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 1330310132131 its reverse (1312310130331), we get a palindrome (2642620262462).
The spelling of 1330310132131 in words is "one trillion, three hundred thirty billion, three hundred ten million, one hundred thirty-two thousand, one hundred thirty-one".
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