Base | Representation |
---|---|
bin | 10011010111000010001… |
… | …001101101100000000001 |
3 | 11201012000000111020202112 |
4 | 103113002021231200001 |
5 | 133244130432020113 |
6 | 2455102304425105 |
7 | 165055415166365 |
oct | 23270211554001 |
9 | 4635000436675 |
10 | 1330402220033 |
11 | 473247408077 |
12 | 195a11018195 |
13 | 985c18ca453 |
14 | 4856b1b52a5 |
15 | 249180005a8 |
hex | 135c226d801 |
1330402220033 has 4 divisors (see below), whose sum is σ = 1330435938048. Its totient is φ = 1330368502020.
The previous prime is 1330402220029. The next prime is 1330402220047. The reversal of 1330402220033 is 3300222040331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1330402220033 - 22 = 1330402220029 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1330402219990 and 1330402220008.
It is not an unprimeable number, because it can be changed into a prime (1330402220053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16799753 + ... + 16878758.
It is an arithmetic number, because the mean of its divisors is an integer number (332608984512).
Almost surely, 21330402220033 is an apocalyptic number.
It is an amenable number.
1330402220033 is a deficient number, since it is larger than the sum of its proper divisors (33718015).
1330402220033 is an equidigital number, since it uses as much as digits as its factorization.
1330402220033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33718014.
The product of its (nonzero) digits is 2592, while the sum is 23.
Adding to 1330402220033 its reverse (3300222040331), we get a palindrome (4630624260364).
The spelling of 1330402220033 in words is "one trillion, three hundred thirty billion, four hundred two million, two hundred twenty thousand, thirty-three".
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