13304152504113 has 4 divisors (see below), whose sum is σ = 17738870005488. Its totient is φ = 8869435002740.

The previous prime is 13304152504109. The next prime is 13304152504217. The reversal of 13304152504113 is 31140525140331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13304152504113 - 2² = 13304152504109 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13304152504813) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2217358750683 + ... + 2217358750688.

It is an arithmetic number, because the mean of its divisors is an integer number (4434717501372).

Almost surely, 2^{13304152504113} is an apocalyptic number.

It is an amenable number.

13304152504113 is a deficient number, since it is larger than the sum of its proper divisors (4434717501375).

13304152504113 is an equidigital number, since it uses as much as digits as its factorization.

13304152504113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4434717501374.

The product of its (nonzero) digits is 21600, while the sum is 33.

Adding to 13304152504113 its reverse (31140525140331), we get a palindrome (44444677644444).

The spelling of 13304152504113 in words is "thirteen trillion, three hundred four billion, one hundred fifty-two million, five hundred four thousand, one hundred thirteen".