Base | Representation |
---|---|
bin | 111101111101000001… |
… | …1110011101101011001 |
3 | 110201102002100210002122 |
4 | 1323322003303231121 |
5 | 4134433321233423 |
6 | 141041505311025 |
7 | 12416651033054 |
oct | 1737203635531 |
9 | 421362323078 |
10 | 133044321113 |
11 | 514730616a0 |
12 | 21950335475 |
13 | c713806682 |
14 | 662192ba9b |
15 | 36da25e8c8 |
hex | 1efa0f3b59 |
133044321113 has 4 divisors (see below), whose sum is σ = 145139259408. Its totient is φ = 120949382820.
The previous prime is 133044321107. The next prime is 133044321133. The reversal of 133044321113 is 311123440331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 133044321113 - 26 = 133044321049 is a prime.
It is not an unprimeable number, because it can be changed into a prime (133044321103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6047469131 + ... + 6047469152.
It is an arithmetic number, because the mean of its divisors is an integer number (36284814852).
Almost surely, 2133044321113 is an apocalyptic number.
It is an amenable number.
133044321113 is a deficient number, since it is larger than the sum of its proper divisors (12094938295).
133044321113 is a wasteful number, since it uses less digits than its factorization.
133044321113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12094938294.
The product of its (nonzero) digits is 2592, while the sum is 26.
Adding to 133044321113 its reverse (311123440331), we get a palindrome (444167761444).
The spelling of 133044321113 in words is "one hundred thirty-three billion, forty-four million, three hundred twenty-one thousand, one hundred thirteen".
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