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133052120124155 = 526939881330867
BaseRepresentation
bin11110010000001010011100…
…010110110100101011111011
3122110002122210000111012102122
4132100022130112310223323
5114414411220222433110
61150551144500351455
740011461366542361
oct3620123426645373
9573078700435378
10133052120124155
11394380a616a681
1212b0a4859a558b
1359319b816a72b
1424bda851cd631
15105aece872255
hex79029c5b4afb

133052120124155 has 8 divisors (see below), whose sum is σ = 159721832150352. Its totient is φ = 106402170765088.

The previous prime is 133052120124109. The next prime is 133052120124167. The reversal of 133052120124155 is 551421021250331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 133052120124155 - 214 = 133052120107771 is a prime.

It is a super-2 number, since 2×1330521201241552 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4940651969 + ... + 4940678898.

It is an arithmetic number, because the mean of its divisors is an integer number (19965229018794).

Almost surely, 2133052120124155 is an apocalyptic number.

133052120124155 is a deficient number, since it is larger than the sum of its proper divisors (26669712026197).

133052120124155 is an equidigital number, since it uses as much as digits as its factorization.

133052120124155 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9881333565.

The product of its (nonzero) digits is 36000, while the sum is 35.

Adding to 133052120124155 its reverse (551421021250331), we get a palindrome (684473141374486).

The spelling of 133052120124155 in words is "one hundred thirty-three trillion, fifty-two billion, one hundred twenty million, one hundred twenty-four thousand, one hundred fifty-five".

Divisors: 1 5 2693 13465 9881330867 49406654335 26610424024831 133052120124155