Base | Representation |
---|---|
bin | 11110010000001010011100… |
… | …010110110100101011111011 |
3 | 122110002122210000111012102122 |
4 | 132100022130112310223323 |
5 | 114414411220222433110 |
6 | 1150551144500351455 |
7 | 40011461366542361 |
oct | 3620123426645373 |
9 | 573078700435378 |
10 | 133052120124155 |
11 | 394380a616a681 |
12 | 12b0a4859a558b |
13 | 59319b816a72b |
14 | 24bda851cd631 |
15 | 105aece872255 |
hex | 79029c5b4afb |
133052120124155 has 8 divisors (see below), whose sum is σ = 159721832150352. Its totient is φ = 106402170765088.
The previous prime is 133052120124109. The next prime is 133052120124167. The reversal of 133052120124155 is 551421021250331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 133052120124155 - 214 = 133052120107771 is a prime.
It is a super-2 number, since 2×1330521201241552 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4940651969 + ... + 4940678898.
It is an arithmetic number, because the mean of its divisors is an integer number (19965229018794).
Almost surely, 2133052120124155 is an apocalyptic number.
133052120124155 is a deficient number, since it is larger than the sum of its proper divisors (26669712026197).
133052120124155 is an equidigital number, since it uses as much as digits as its factorization.
133052120124155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9881333565.
The product of its (nonzero) digits is 36000, while the sum is 35.
Adding to 133052120124155 its reverse (551421021250331), we get a palindrome (684473141374486).
The spelling of 133052120124155 in words is "one hundred thirty-three trillion, fifty-two billion, one hundred twenty million, one hundred twenty-four thousand, one hundred fifty-five".
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