Base | Representation |
---|---|
bin | 11000110010000110… |
… | …10111100010001011 |
3 | 1021100021002221220000 |
4 | 30121003113202023 |
5 | 204222113340430 |
6 | 10040132534043 |
7 | 650500314423 |
oct | 143103274213 |
9 | 37307087800 |
10 | 13305215115 |
11 | 57084a1055 |
12 | 26b3a81323 |
13 | 13406a746a |
14 | 9030d9483 |
15 | 52d140e60 |
hex | 3190d788b |
13305215115 has 20 divisors (see below), whose sum is σ = 23850830784. Its totient is φ = 7096114512.
The previous prime is 13305215113. The next prime is 13305215117. The reversal of 13305215115 is 51151250331.
13305215115 is a `hidden beast` number, since 1 + 330 + 5 + 215 + 115 = 666.
It is an interprime number because it is at equal distance from previous prime (13305215113) and next prime (13305215117).
It is not a de Polignac number, because 13305215115 - 21 = 13305215113 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is not an unprimeable number, because it can be changed into a prime (13305215113) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 16425787 + ... + 16426596.
Almost surely, 213305215115 is an apocalyptic number.
13305215115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13305215115 is a deficient number, since it is larger than the sum of its proper divisors (10545615669).
13305215115 is an equidigital number, since it uses as much as digits as its factorization.
13305215115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32852400 (or 32852391 counting only the distinct ones).
The product of its (nonzero) digits is 2250, while the sum is 27.
Adding to 13305215115 its reverse (51151250331), we get a palindrome (64456465446).
The spelling of 13305215115 in words is "thirteen billion, three hundred five million, two hundred fifteen thousand, one hundred fifteen".
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