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1330525201 = 6451206251
BaseRepresentation
bin100111101001110…
…0011010000010001
310102201121200110011
41033103203100101
510211103301301
6340005434521
744654164135
oct11723432021
93381550404
101330525201
11623057305
1231170ba41
13182865025
14c89c93c5
157bc1ea51
hex4f4e3411

1330525201 has 4 divisors (see below), whose sum is σ = 1330737904. Its totient is φ = 1330312500.

The previous prime is 1330525193. The next prime is 1330525219. The reversal of 1330525201 is 1025250331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1330525201 - 23 = 1330525193 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1330525241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 96675 + ... + 109576.

It is an arithmetic number, because the mean of its divisors is an integer number (332684476).

Almost surely, 21330525201 is an apocalyptic number.

It is an amenable number.

1330525201 is a deficient number, since it is larger than the sum of its proper divisors (212703).

1330525201 is an equidigital number, since it uses as much as digits as its factorization.

1330525201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 212702.

The product of its (nonzero) digits is 900, while the sum is 22.

The square root of 1330525201 is about 36476.3649641792. The cubic root of 1330525201 is about 1099.8691858213.

Adding to 1330525201 its reverse (1025250331), we get a palindrome (2355775532).

The spelling of 1330525201 in words is "one billion, three hundred thirty million, five hundred twenty-five thousand, two hundred one".

Divisors: 1 6451 206251 1330525201