Base | Representation |
---|---|
bin | 1100000110011110011111… |
… | …1001000111000000100011 |
3 | 1202002222120111102120000101 |
4 | 3001213213321013000203 |
5 | 3220443431440123043 |
6 | 44144230205003231 |
7 | 2542166214563536 |
oct | 301474771070043 |
9 | 52088514376011 |
10 | 13305404223523 |
11 | 426a8768a4125 |
12 | 15aa814b53517 |
13 | 756904305709 |
14 | 33ddb0baca1d |
15 | 1811864e724d |
hex | c19e7e47023 |
13305404223523 has 8 divisors (see below), whose sum is σ = 14005801099520. Its totient is φ = 12605018591880.
The previous prime is 13305404223521. The next prime is 13305404223541. The reversal of 13305404223523 is 32532240450331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13305404223523 - 21 = 13305404223521 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13305404223521) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 325863 + ... + 5168848.
It is an arithmetic number, because the mean of its divisors is an integer number (1750725137440).
Almost surely, 213305404223523 is an apocalyptic number.
13305404223523 is a deficient number, since it is larger than the sum of its proper divisors (700396875997).
13305404223523 is a wasteful number, since it uses less digits than its factorization.
13305404223523 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5622177.
The product of its (nonzero) digits is 259200, while the sum is 37.
Adding to 13305404223523 its reverse (32532240450331), we get a palindrome (45837644673854).
The spelling of 13305404223523 in words is "thirteen trillion, three hundred five billion, four hundred four million, two hundred twenty-three thousand, five hundred twenty-three".
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