133055040026035 has 16 divisors (see below), whose sum is σ = 169118784856800. Its totient is φ = 100146697570816.

The previous prime is 133055040025993. The next prime is 133055040026057. The reversal of 133055040026035 is 530620040550331.

It is not a de Polignac number, because 133055040026035 - 2⁴³ = 124258947003827 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133055040025985 and 133055040026003.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 280392805 + ... + 280866934.

It is an arithmetic number, because the mean of its divisors is an integer number (10569924053550).

Almost surely, 2^{133055040026035} is an apocalyptic number.

133055040026035 is a deficient number, since it is larger than the sum of its proper divisors (36063744830765).

133055040026035 is a wasteful number, since it uses less digits than its factorization.

133055040026035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 561262550.

The product of its (nonzero) digits is 162000, while the sum is 37.

Adding to 133055040026035 its reverse (530620040550331), we get a palindrome (663675080576366).

The spelling of 133055040026035 in words is "one hundred thirty-three trillion, fifty-five billion, forty million, twenty-six thousand, thirty-five".